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28x^2-39x+8=0
a = 28; b = -39; c = +8;
Δ = b2-4ac
Δ = -392-4·28·8
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-39)-25}{2*28}=\frac{14}{56} =1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-39)+25}{2*28}=\frac{64}{56} =1+1/7 $
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